線上遊戲排行榜2013/2014,進擊的巨人線上看,candy crush saga外掛,正妹寫真三圍

1.試將下列各式化為極式

(1) cos320°-i*sin220°

=cos(360-40)-j*sin(180+40);;j=i

=cos40+jsin40

=e^(2πj/9)

其中40π/180=2π/9

(2) cos507°-i*sin327°

=cos(360+147)-j*sin(180+147)

=cos147+j*sin147

=e^(49πj/60)

其中147π/180=49π/60

(3) -(sin18°+j*cos18°)

=-(sin(90-72)+j*cos(90-72))

=-(cos72+j*sin72)

=-e^(2π/5)

其中72π/180=2π/5

(4) sin125°+i*cos235°

=sin(90+35)+j*cos(270-35)

=cos35-jsin35

=e^(-7π/36)

其中35π/180=7π/36

2.設z=2(cosπ/3+i*sinπ/3),求Arg(i●z)=?

Ans: j=i

j=(cos90+j*sin90)=e^(πj/2)

j*z=e^(πj/2)*2*e^(πj/3)=2e^(5πj/6)

Arg(j*z)=5π/6=150°

3.z1=-2+i, z2=3-i, Arg(z1)=θ1,Arg(z2)=θ2 ,則w3=Arg(z1)+Arg(z2)=?

Ans: Q=θ

Q1=atan(1/-2)=153.435°

r1=√(1+4)=√5

z1=√5(-2/√5+j/√5)

=√5(cos(153.435)+jsin(153.435))

Arg(z1)=153.435°

Q2=atan(-1/3)=-18.435°

r2=√(9+1)=√10

z2=3-j

=√10(cos18.435-j*sin18.435)

Arg(z2)=-18.435°

w3=Arg(z1)+Arg(z2)

=153.435°-18.435°

=135°

This entry passed through the Full-Text RSS service — if this is your content and you're reading it on someone else's site, please read the FAQ at fivefilters.org/content-only/faq.php#publishers. Five Filters recommends: 'You Say What You Like, Because They Like What You Say' - http://www.medialens.org/index.php/alerts/alert-archive/alerts-2013/731-you-say-what-you-like-because-they-like-what-you-say.html