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電流電阻求解
Jan 1st 2014, 08:53

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因I1=I2, 利用電流分配定理 可得知R1=R2 ------ 設R1=R2=R, R&#39;=R1//R2 = R&#39;=R/2 V=IR 10=0.04(100+100+R&#39;) 250=200+R&#39; R&#39;=50(歐姆) 故R1=2R&#39;=2*50= 100(歐姆) 記得40mA要改為0.04A哦~~ __^ R1//R2 是100+100/100*100嗎?? 不是~~~~我說的R&#039;=R1//R2(//是指平行<sep/>...
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    線上遊戲排行榜2013/2014,進擊的巨人線上看,candy crush saga外掛,正妹寫真三圍

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